Use VSEPR model to draw the structures of OSF 4 and XeF 4 (indicate the lone pair(s) on central atom) and specify their geometry.
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
According to VSEPR theory two lone pairs out of six electron pairs are trans to each other to have minimum repulsion. The shape of XeF 4 is square planar and geometry is octahedral with sp 3 d 2 hybridisation. The molecule looks like :
In OSF 4 , there are five electron pairs and all are bond pairs. So geometry is trigonal bipyramidal. As double bond creates more repulsion than singles bond, the double bond acquires one of equatorial position of trigonal bipyramidal to have minimum repulsions.
The structure looks like: 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems